If it's not what You are looking for type in the equation solver your own equation and let us solve it.
D( x )
2*x+5 = 0
2*x+5 = 0
2*x+5 = 0
2*x+5 = 0 // - 5
2*x = -5 // : 2
x = -5/2
x in (-oo:-5/2) U (-5/2:+oo)
(8*x^3+4*x^2+100)/(2*x+5) = 0
8*x^3+4*x^2+100 = 0
4*(2*x^3+x^2+25) = 0
2*x^3+x^2+25 = 0
{ 1, -1, 5, -5, 25, -25 }
1
x = 1
2*x^3+x^2+25 = 28
1
-1
x = -1
2*x^3+x^2+25 = 24
-1
5
x = 5
2*x^3+x^2+25 = 300
5
-5
x = -5
2*x^3+x^2+25 = -200
-5
25
x = 25
2*x^3+x^2+25 = 31900
25
-25
x = -25
2*x^3+x^2+25 = -30600
-25
{ 1/2, -1/2, -1/2, 1/2, 5/2, -5/2, -5/2, 5/2, 25/2, -25/2, -25/2, 25/2 }
1/2
x
1/2
2*x^3+x^2+25 = 25.5
1/2
-1/2
x
-1/2
2*x^3+x^2+25 = 25
-1/2
-1/2
x
-1/2
2*x^3+x^2+25 = 25
-1/2
1/2
x
1/2
2*x^3+x^2+25 = 25.5
1/2
5/2
x
5/2
2*x^3+x^2+25 = 62.5
5/2
-5/2
x
-5/2
2*x^3+x^2+25 = 0
-5/2
x+5/2
2*x^2-4*x+10
2*x^3+x^2+25
x+5/2
-2*x^3-5*x^2
25-4*x^2
4*x^2+10*x
10*x+25
-10*x-25
0
2*x^2-4*x+10 = 0
DELTA = (-4)^2-(2*4*10)
DELTA = -64
DELTA < 0
x in { -5/2}
4*(x+5/2) = 0
(4*(x+5/2))/(2*x+5) = 0
x+5/2 = 0 // - 5/2
x = -5/2
x in { -5/2}
x belongs to the empty set
| b-16=49 | | 4.37x+3.44(1/3x)=62.76 | | 9+4x=6x+5 | | 2x-y=19 | | (x^3+9)(x^2+4x)= | | 3x+3y=30 | | (x^3+3x+3)(x^2-x-1)=0 | | (x^2+5x+4)(3x^2+5)=0 | | 25=5+.50n | | (4x^3+2x^2+3x+4)(4x+4)=0 | | (4x^2+3x+7)(8x-5)=0 | | y+3(2)+3y+4(2)=70 | | (8x^2+7x+9)(7x^3+9x)=0 | | (3x^2+2x+6)(6x^2-2)=0 | | (3x^2+4x+4)(2x-4)=0 | | 5(1)= | | (6x^3-3x^2+5x+9)(7x+9)=0 | | (18/x)X100=0.4 | | (9r-18)/2=45 | | 5(0)= | | 2(6b-1)=5(5b-3) | | 14/3x=6/2x-5 | | (8x^2-4x+6)(5x+5)=0 | | -35-(-38)=x/5 | | (5x^2-2x-5)(3x+9)=0 | | 59+5y-19=16y-14-2y | | 59+5y-19=16-14-2y | | (2/x-3)-(4/x+3)=(8/x^2-9) | | (5x^2-3x-5)(6x^2+5x+6)=0 | | (x^2+x+9)(x-6)=0 | | (6x^2-3x-6)(3x+6)=0 | | (2x^2+5x+5)(7x-3)=0 |